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Re: computer-go: What makes a ladder
> Instead of blindly following rules, you should try to read the ladder.
> As it has a branching factor of 1 for each black move and 2 for each
> white move, this is not difficult.
But a rule is still far cheaper, if you can find one that actually
works. Most of the programmers have complained that evaluation is
really expensive, so I don't see where it hurts trying to find
something cheaper. Even if you don't succeed, you are likely to learn
something.
Don
Date: Fri, 2 Feb 2001 14:33:08 +0000
From: Nick Wedd <Nick@xxxxxxxxxxxxxxxxx>
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Njoroge <Njoroge@xxxxxxxxxxxxxxxxx> writes
>I belive that you are wrong.
>
>The rules that fails the ladder is that the Opponent stone has less than 2
>liberties.
Instead of blindly following rules, you should try to read the ladder.
As it has a branching factor of 1 for each black move and 2 for each
white move, this is not difficult.
>
>-.-.-.-.-.-O-.-.-.-.-
> . . . . O X . . . .
> . . . O X X O X . .
> . . O X X O . . . .
> . O X X O . . . . .
> . O X O . . . . . .
> . . O . . . . . . .
> . . . . . . . . . .
>
>The ladder has now been extended and it is black to play. The correct
>orientation of my original diagram is
But white's last move was bad.
Nick
--
Nick Wedd nick@xxxxxxxxxxxxxxxxx