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RE: computer-go: Rules clarification



Well, got confused.

My understanding of "ko" is that "no same board shape can be repeated". In that case, after e1-c1-d1-pass, it's # to play, and if # plays e1 again, it violates the rule of ko and thus loses the game.

-- Mousheng Xu


From: "Russ Williams" <russw@xxxxxxxxxxxxxxxxx>
Reply-To: computer-go@xxxxxxxxxxxxxxxxx
To: <computer-go@xxxxxxxxxxxxxxxxx>
Subject: RE: computer-go: Rules clarification
Date: Tue, 19 Mar 2002 08:59:04 -0600

> -------------
> 2|# # # O O O O|2 # to play
> 1|. # . # . O .|1
> -------------
>
> There are really two questions here:
> 1: How will the game continue, assuming skilful play?
> 2: What, then, will be the result?
>
> We are to assume Japanese rules.
>
> 1.
> I can see two possible lines of skilful play:
> B pass
> W pass
> and
> B C1
> W pass
> B pass
>
> 2.
> After either line, the result is seki. So no points are scored on the
> board. The prisoners (unspecified) and the komi (unspecified) are added
> up, and the sum determines the result.
>
> Nick

I assume the point of the original question was "wouldn't it be skillful
play of black to keep playing "B-E1 W-D1 B-D2 W-pass B-E1 ...?" so that the
game never terminates, rather than suffer a loss. Simple ko doesn't prevent
black from doing that, right? It does raise an issue with the notion of
"the game terminates after both players pass" in that I have no incentive to
pass if I'm going to lose. :) So what prevents this scenario other than the
assumption that black is a good sport?

Russ


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