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Re: computer-go: Ko



Yikes, you're right!

Someone here had said something about this in their ko-detection routine.

Perhaps the correct statement is simply:

A move which is the first to ever occupy a given point cannot be a ko violation.

I'll have to fix my code...

On Tuesday, June 3, 2003, at 09:33 PM, Gunnar Farnebäck wrote:

Peter Drake wrote:
Is the following statement true?

If a stone played at a point is the first stone to ever occupy that
point, no subsequent full-board position can be identical to a
preceding position.
Definitely not, it doesn't even hold for a basic ko. I.e., assume that
this position has been reached without captures:

......
..OX..
.O.OX.
..OX..
......

Black takes the ko, playing the first stone ever at that vertex

......
..OX..
.OX.X.
..OX..
......

If O immediately recaptures we get a counterexample.

/Gunnar Farnebäck

Peter Drake
Assistant Professor of Computer Science
Lewis & Clark College
http://www.lclark.edu/~drake/