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computer-go: Defeating mirror Go
Hello computer-go,
I think there is a way to defeat any kind of mirror GO if the
super-ko rules is valid(no repeated positions allowed). Here is how:
Create the following pattern:
.,A,B,C,D = empty
X = Black
O = White
Suppose you are white. Play A then B( Black will be mirroring the
moves accordingly). This will capture the two black stones while
black will capture the two corresponding white stones.
Your side: Mirror side:
A B X . . . . . . . . . O . .
X X O . . . . . . . . . X O O
O O . . . . . . . . . . . X X
. . . . . . . . . . . . . . .
After playing A,B:
Your side: Mirror side:
O O X . . . . . . . . . O X X
. . O . . . . . . . . . X C D
O O . . . . . . . . . . . X X
. . . . . . . . . . . . . . .
Now white plays C then D. Black can't mirror D because in doing so the
initial position would be repeated which isn't allowed if the super-ko
rule is valid!
I want to emphasize that the above works regardless if you are
mirroring through the center point or trough a vertical or horizontal
axis.
--
Best regards,
Roland mailto:goprog@xxxxxxxxxxxxxxxxx