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computer-go: Defeating mirror Go



Hello computer-go,

  I think there is a way to defeat any kind of mirror GO if the
  super-ko rules is valid(no repeated positions allowed). Here is how:
 Create the following pattern:

 .,A,B,C,D = empty
 X = Black
 O = White

 Suppose you are white. Play A then B( Black will be mirroring the
 moves accordingly). This will capture the two black stones while
 black will capture the two corresponding white stones.
 
Your side:                    Mirror side:
 A B X . . . . .           . . . . O . .
 X X O . . . . .           . . . . X O O
 O O . . . . . .           . . . . . X X
 . . . . . . . .           . . . . . . .

 After playing A,B:

Your side:                    Mirror side:
 O O X . . . . .           . . . . O X X
 . . O . . . . .           . . . . X C D
 O O . . . . . .           . . . . . X X
 . . . . . . . .           . . . . . . .
 
Now white plays C then D. Black can't mirror D because in doing so the
initial position would be repeated which isn't allowed if the super-ko
rule is valid!

I want to emphasize that the above works regardless if you are
mirroring through the center point or trough a vertical or horizontal
axis.

-- 
Best regards,
 Roland                          mailto:goprog@xxxxxxxxxxxxxxxxx