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Frank de Groot wrote:
From: "Erik van der Werf" <E.vanderWerf@xxxxxxxxxxxxxxxxx>
So again, how many bit's does your "secret" scheme save?
I use 64 bits.
You misunderstand the question.
If your 64-bit keys give a colision probability p for searching, let's
say, 10^9 positions.
How many bits extra would you need to get the same colision probability
for random keys?
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