Re: [computer-go] Groups, liberties, and such

[Valery <valery@xxxxxxxxxxx>]

drd@xxxxxxxxxxxxxxxxx a écrit :

> When a move connects 2 strings,  isn't it easy and fast to calculate 
> the liberty count of the newly combined string? 
>   new_count = old_string_A_count + old_string_B_count - 1 + LNC.
>
> LNC means Liberties Not in Common.  For the newly placed stone (that does
> the connecting), we look at the 4 neighbor points.   If they are empty,
> we tally 1 if they are not liberties of EITHER of the OLD strings.
> This idea is easily extended for connections of 3 or 4 groups.
>
> When connecting 2 groups, you would have to look at 6 points at most,
> the 2 possible new liberties,  and the 3 possible points around these new 
> liberties to check if they touch the old group.
>  
That doesn't work because the 2 strings may have common liberties far 
away from the connecting stone.

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