Re: computer-go: Rules clarification

[Nick Wedd <nick@xxxxxxxxxxxxx>]

In message <OCEMIBLADPONKHPIDIHPCEIAHGAB.hsr@xxxxxxxxxxxxxxxxx>, Scott Roy
<hsr@xxxxxxxxxxxxxxxxx> writes
>
>    A B C D E F G
>    -------------
>  7|O O O O O O O|7
>  6|O O O O O O O|6
>  5|O O O O O O O|5    # to play
>  4|O O O O O O O|4
>  3|O O O O O O O|3
>  2|# # # O O O O|2
>  1|. # . # . O .|1
>    -------------
>    A B C D E F G
>
>White has obviously captured more stones, so regardless of the scoring rule
>he wins if the game ends here.

There are two errors in this statement.

1.
Maybe this position was achieved by Black passing repeatedly, and Black
has captured more stones.

2.
With area (Chinese) scoring, prisoners are irrelevant.

>  Using the standard ko rule, this positions
>is:
>
>A) A win for white, by precedent or adjudication.
>B) A win for white, because black runs out of stones.

The supply of stones is unlimited

>C) A draw, because black can play E1-C1-D1 forever.

If Black does this for long enough, and you are counting prisoners, then
White will have more prisoners.

Nick
-- 
Nick Wedd    nick@xxxxxxxxxxxxxxxxx